Thread: problems with find command and variables in bash

ok, if run

code:

find . -path 'abc' -not -path '*xyz'

everything functions expect to.
if put after -not variable , run

code:

find . -path 'abc' $variable

it doesn't function properly.

here?

are there quotes around *xyz in variable value? not interpretted correctly shell if in variable's value. in other words, should assign variable this:

code:

variable='-not -path *xyz'

not this

code:

variable="-not -path '*xyz'"

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